Compares two lists and returns true, if all items are equal.

Compares two animation curves and returns true, if their keys are equal.

Obsolete - use EaseOnCurve(AnimationCurve, Single, Single, Single) instead!

Obsolete - use EaseOnCurve(AnimationCurve, Color, Color, Single) instead!

Obsolete - use EaseOnCurve(AnimationCurve, Vector3, Vector3, Single) instead!

Tests if a given renderer is visible from a specific camera.

Tries to load an asset of type T from path.

Automatically scales your pixel definitions for widths, heights or relative screen positions for high density (e.g. Retina) displays. This either returns pixels, as it is, or pixels * 2 if we have a high density display.

Automatically scales your pixel definitions for widths, heights or relative screen positions for high density (e.g. Retina) displays. This either returns pixels, as it is, or pixels * 2 if we have a high density display.

Inverts the scale applied via Scale(Single). This is useful if you're grabbing dimensions from objects while we are in high density mode.

Inverts the scale applied via Scale(Single). This is useful if you're grabbing dimensions from objects while we are in high density mode.

Automatically scales only the width and height of a rectangle for high density (e.g. Retina). This is useful for rectangles that already have a correct position but the wrong dimensions. Use with caution! ;-)

Creates a user readable diff between two objects of same type. Currently implements special handling for: IList (arrays and lists) and AnimationCurve.

Tries to put a into a readable form, if ToString fails to do so.

Set this to true for testing high density screen layouts etc. If this is true, IsHighDensityDisplay always returns true regardless of whether we actually have a high density display. This is useful to test high density GUI layouts in the editor (which never has a Retina display ;-) ).

Are we on a high density screen (e.g. Retina display)?

Returns true, if according to Screen.width and Screen.height, we are in portrait mode; and false, if we are more likely in landscape mode (according to Screen.width and Screen.height). A square screen will return false (we define square as "still landscape" ;-) ).